3000 exercise books are arranged in 3 piles.the first pile has 10 more books than the second pile.the number of books in the second pile is twice the number of books in the third pile.how many books are in the third pile?

let x=pile one

x-10=second pile
x/2=third pile

x+(x-10)+(x/2)=3000
2x+x/2=3010
4x+x=6020
5x=6020
x=1204

The third pile is x/2, so the third pile has 1204/2, or 602 books.

To solve this problem, let's break it down step by step.

Let's assume the number of books in the third pile is represented by 'x'.

According to the problem, the second pile has twice the number of books in the third pile. So, the number of books in the second pile is 2x.

The first pile has 10 more books than the second pile. So, the number of books in the first pile is 2x + 10.

Now, we know that the total number of exercise books is 3000. Therefore, we can write an equation based on the given information:

x + 2x + (2x + 10) = 3000

Simplifying the equation, we get:

5x + 10 = 3000

Subtracting 10 from both sides:

5x = 2990

Dividing both sides by 5:

x = 598

Therefore, the number of books in the third pile is 598.