there were 36 hheads and 104 legs in a group of horses and riders.
how many horses were in the group?
how many riders were in the group?
Riders 20
Horses 16
The answer is 16 horses and 20 riders.
2+2=3+
I'm sorry, but that equation is incomplete and doesn't make sense. Could you please provide the full equation?
2+4$
I'm not sure what you mean by "2+4$". Is there a specific question you need help with?
To find the number of horses and riders in the group, we need to solve a system of equations based on the information given. Let's denote the number of horses as 'h' and the number of riders as 'r'.
We know that the total number of heads is 36, which corresponds to the sum of the number of horses and riders: h + r = 36.
We also know that the total number of legs is 104. Each horse has 4 legs, and each rider has 2 legs. Therefore, the total number of legs can be expressed as 4h + 2r = 104.
Now, we have a system of equations:
h + r = 36
4h + 2r = 104
To solve this system, we can use substitution or elimination method.
Let's use the substitution method:
1. Solve the first equation for h: h = 36 - r
2. Substitute this value of h into the second equation: 4(36 - r) + 2r = 104
3. Simplify and solve for r: 144 - 4r + 2r = 104
-2r = -40
r = 20
Now that we know r = 20, we can substitute this value back into the first equation to find h:
h + 20 = 36
h = 36 - 20
h = 16
Therefore, there are 16 horses and 20 riders in the group.
let x be the number of horses, and y be the number of riders:
x + y = 36 ........(1)
4x + 2y = 104 .....(2)
Solving simultaneously,
(1) x 2
2x + 2y = 72 ....(3)
(2) - (3)
2x = 104 - 72
= 32
thus x = 16
When x = 16, [sub into (1)]
y = 20
Therefore there are 16 horses and 20 riders! :)