Friday

August 22, 2014

August 22, 2014

Posted by **Jonathan** on Tuesday, September 27, 2011 at 7:14pm.

1.Which of the folowing is another representation of (-3,pi)?

(3,120degree)

(3,0 degree)I think it is this one??

((-3,0 degree)

2.Which is not a representation of (5,150 degree)

(-5,-30 degree)I think it is this one?

(-5,330 degree)

(5,510 degree)

3.Give 3 representations of (3,240 degree)One has to be in radians

My choices are: (3,600 degrees)

(3,-120 degree degree)

(-3,pi/3)

4.Give 3 representations of (-6,3pi/4)one has to be radians

I gave-(-6,495 degrees)

(-6,-225 degrees)

(6,-pi/4)

- Pre-Calc -
**Henry**, Thursday, September 29, 2011 at 4:58pm1. (-3,pi) = -3cos(pi) + i(-3)sin(pi) =

3 + io = 3.

(3,120deg) = -1.5 + i2.6

(3,0deg) = 3 + i0 = 3.

(-3,0deg) = -3 + i0 = -3.

2. (5,150deg) = -4.33 + i2.5

(-5,-30deg) = -4.33 + i2.5

(-5,330deg) = -4.33 + i2.5

(5,510deg) = -4.33 + i2.5

My calculations show that all of # 2 is

identical.

3. (3,240deg) = -1.5 - i2.6

(3,600deg) = -1.5 - i2.6

(3,-120deg) = -1.5 - i2.6

(-3,pi/3) = -1.5 - i2.6

Good!!

4. (-6,3pi/4) = 4.24 - i4.24

(-6,495deg) = 4.24 - i4.24

(-6,-225deg) = 4.24 -i4.24

(6,-pi/4) = 4.24 - i4.24.

Very good!

**Related Questions**

Pre-Calc-Please check I'm desperate - Please check my answers I really need to ...

Pre-Calc - Please check my answers;This are polar coordinates we're studying-I'm...

Pre-Calc - Can anyone direct me to learn more about polar coordinates. I'm in ...

Pre-Calc - I know about Descartes Rule but I don't really get how to figure this...

Studying for Calc - I have a quiz on derivatives coming up and I really want to ...

pre calc.Math - Please help me any one of these please! Thank You to any one r=...

Pre-Calc-Please check my answer-I think its correc - Could someone please check ...

pre-calc help - Convert the rectangular coordinates to polar coordinates with r...

pre-calc help - Convert the rectangular coordinates to polar coordinates with r...

Pre-Calc - How do I calculate the coordinates for the Polar equation r=...