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A 70.0-kg runner has a speed of 5.90 m/s at one instant during a long-distance event.What is the runner's kinetic energy at this instant? If he doubles his speed to reach the finish line, by what factor does his kinetic energy change?

  • Physics -

    1. KE=0.5mV^2=0.5 * 70 * (5.90)^2=1218J

    2. 2^2 = 4 = The factor by which the KE
    is incrased.

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