Physics
posted by Imani .
A person walks 15.0° north of east for 3.70 km. How far due north and how far due east would she have to walk to arrive at the same location?

It's easiest to just draw a diagram.
Start out at (0,0) and draw a line 3.7 long, at an angle of 15deg up from horizontal.
Now you have a right triangle, with hypotenuse 3.7, and
height = 3.7 sin 15 = 0.96 (north)
base = 3.7 cos 15 = 3.57 (east)