Homework Help: Physics

Posted by Imani on Tuesday, September 27, 2011 at 6:41pm.

A person walks 15.0° north of east for 3.70 km. How far due north and how far due east would she have to walk to arrive at the same location?

Physics - Steve, Wednesday, September 28, 2011 at 4:48am
It's easiest to just draw a diagram.

Start out at (0,0) and draw a line 3.7 long, at an angle of 15deg up from horizontal.

Now you have a right triangle, with hypotenuse 3.7, and
height = 3.7 sin 15 = 0.96 (north)
base = 3.7 cos 15 = 3.57 (east)

Answer this Question

Related Questions

Physics.. please help!!!!! - A person walks 28.2◦ north of east for 3....
PHYSICS - A person walks 11.2 ◦ north of east for 4.06 km. Another ...
Physics - A person walks 13.9◦ north of east for 2.51 km. Another ...
Physics - A person walks 13.9◦ north of east for 2.51 km. Another ...
Physics - A person walks 28.2◦ north of east for 3.33 km. Another ...
physics - A person walks 11.0° north of east for 3.30 km. How far due north ...
Physics - A person walks 23.0° north of east for 2.60 km. How far due north ...
physics - A person walks 41° north of east for 3.77 km. How far would ...
Physics - A person walks 24.0° north of east for 2.80 km. How far would ...
physics - A person walks 25.0° north of east for 4.00 km. How far would the ...

For Further Reading

First Name:
School Subject:
Answer: