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April 18, 2015

April 18, 2015

Posted by **Elle** on Tuesday, September 27, 2011 at 12:21pm.

- Trig! -
**Steve**, Tuesday, September 27, 2011 at 3:09pmSounds like a good justification to me. Oh, did you mean prove them? In that case, using the identities,

cos(a-b) = cos(a + (-b)) = cos(a) cos(-b) - sin(a) sin(-b)

= cos(a)cos(b) + sin(a) sin(b)

sin(a-b) = sin(a + (-b)) = sin(a) cos(-b) + cos(a) sin(-b)

= sin(a) cos(b) - cos(a) sin(b)

- Trig! -
**Bruce**, Sunday, November 6, 2011 at 3:13pmSin2x

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