What is the slant height of a right pyramid with a surface area of 65.5 meters squared and a base perimeter of 14 metres?

If the pyramid has n sides of length s, then there are n triangles, each with area 1/2*s*h

A = n * 1/2 * s * h
Now, n*s = p
Hence the formula A = ph/2
So, 65.5 = 7h
h = 9.36

Sure it wasn't 66.5? That would give a nice h=9.5