A baseball pitcher can throw a baseball at a velocity of 44.5 m/s. If the mass of the ball is 0.12 kg and the pitcher has it in his hand over a distance of 1.79 m, what is the average force exerted by the pitcher on the ball?

Any ideas?

To find the average force exerted by the pitcher on the ball, you can use Newton's second law of motion, which states that force is equal to the product of mass and acceleration (F = m * a).

In this case, the mass of the ball is given as 0.12 kg, and we need to calculate the acceleration. Since we know the initial velocity (0 m/s) and the final velocity (44.5 m/s) of the ball, we can use the following equation to find the acceleration:

v² = u² + 2as,

where:
v = final velocity,
u = initial velocity,
a = acceleration,
s = distance traveled.

Rearranging the equation to solve for acceleration (a), we have:

a = (v² - u²) / (2s),

Substituting the known values, we get:

a = (44.5 m/s)² / (2 * 1.79 m).

Now we can calculate the acceleration.