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November 25, 2014

November 25, 2014

Posted by **Pauline Duma** on Monday, September 26, 2011 at 6:29pm.

- math -
**MathMate**, Monday, September 26, 2011 at 6:41pmThe height H of the building can be found from the equation:

tan(8°)=H/100

or

H=100tan(8°) ....(1)

After he "backed-up" to a distance of D from the building, the new relation with the height is:

tan(1°48')=H/D

or

D=H/tan(1°48')....(2)

So substitute H from (1) into (2) to get

D=100tan(8°)/tan(1°48')

Can you take it from here?

(The answer is around 450m)

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