Posted by **Pauline Duma ** on Monday, September 26, 2011 at 6:29pm.

john is standing 100 metres away from a building.the angle of elevationto the top of the building is8 degrees .He now walks straight away from the building.When he stopes,the angle of elevation is only 1 degree and 48 seconds.How far away is now from the base of the building.

- math -
**MathMate**, Monday, September 26, 2011 at 6:41pm
The height H of the building can be found from the equation:

tan(8°)=H/100

or

H=100tan(8°) ....(1)

After he "backed-up" to a distance of D from the building, the new relation with the height is:

tan(1°48')=H/D

or

D=H/tan(1°48')....(2)

So substitute H from (1) into (2) to get

D=100tan(8°)/tan(1°48')

Can you take it from here?

(The answer is around 450m)

## Answer This Question

## Related Questions

- math - john is standing 100 metres away from a building.the angle of elevationto...
- Math - Fred was measuring the height of a building. He stood standing at some ...
- math - A man walks directly from point A towards the foot of a tall building ...
- Pre-Calculus - 1.The angle of elevation to top of a building from a point on the...
- math - Richard is standing between two buildings in a town house development.The...
- math - Richard is standing between two buildings in a town house development.The...
- math - a tower 7 metres high stands on top of building which is 9 metres high. ...
- Maths - I have a diagram in which AB is a vertical cliff. BC is a vertical ...
- Trigonometry - A building is 50 feet high. At a distance away from the building...
- Trig - a person who eyes are 5 feet above the ground observes the top of a ...

More Related Questions