posted by marina .
in the xy coordinate plane point b (-3,2) and point d (3,-4)are opposite vertices of square abcd if point h is the midpoint of line segment bc what is the area of triangle ahd ?
If you plot the points, you can see that a = (-3,-4) and h = (0,2).
So, the base of ahd is the line ad with length 6. The height of the triangle is also 6.
So, A(ahd) = 1/2 * 6 * 6 = 18