Posted by michelle on Monday, September 26, 2011 at 10:30am.
What is your question?
Yes, it would be unusal for the mean of a sample of 3 to be 115 or more because there is only a 4.18% chance for this to happen.
P(X >= 115)
= P(X >= (115 - 100) / sqrt(15^2 / 3))
= P(X >= 1.732050808)
= 0.0418
Related Questions
Statistics - Assume that a population is normally distributed with a mean of 100...
statistics - Assume that a population is normally distributed with a mean of 100...
statistics - Assume that a population is normally distributed with a mean of 100...
statistics - Assume that a population is normally distributed with a mean of 100...
statistics - Assume that a population is normally distributed with a mean of 100...
statistics - Assume that a population is normally distributed with a mean of 100...
Statistics - Assume that a population is normally distributed with a mean of 100...
Elementray Statistics - Assume that a population is normally distributed with a ...
Math - Assume that a population is normally distributed with a mean of 100 and a...
statistics - Assume that IQ scores are normally distributed with a mean of 100 ...
For Further Reading