University Physics
posted by me .
A 320.0 m tall tower is built on the Equator. How much faster (in m/s) does a point at the top of the tower move than a point at the bottom. The radius of the Earth is 6400 km.

(R2 R1)*w, where
w is the angular velocity of the Earth in radians/s
R2 and R1 are the distances of the top and bottom of the building from the center of the Earth.
Note that R2  R1 is the height of the building, so you do not need to use the Earth's radius in the calculation.