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December 19, 2014

December 19, 2014

Posted by **Brianna** on Monday, September 26, 2011 at 12:38am.

- college Algebra -
**Steve**, Tuesday, September 27, 2011 at 10:37amg = -2x^2 + bx + c

g = (x-1)(-2x + b-2) remainder b+c-2

In order for 1 to be a root, then x-1 must divide g exactly. That is,

b+c-2 = 0

Using the y-intercept, when x=0, y=5

5 = c

So, b+3 = 0, or b=-3

g = -2x^2 -3x + 5 = (x-1)(-2x - 5)

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