Sunday

April 19, 2015

April 19, 2015

Posted by **Francine** on Sunday, September 25, 2011 at 10:40pm.

- College Algebra 2 -
**Reiny**, Sunday, September 25, 2011 at 10:43pmspeed of slower train = x mph

speed of faster train = x+16 mph

time for slow train to go 190 miles = 190/x

time for fast train to go 270 miles = 270/(x+16)

but the times are the same ....

190/x = 270/(x+16)

cross-multiply and solve for x, easy from here.

Math - the speed of train A is 16 mph slower than the speed of train B. Train A...

algebra - the speed of train A is 8 mph slower than the speed of train B. Train ...

math - the speed of train A is 14 mph slower than train B. Train A travels 190 ...

math - IF the speed of train A is 10 mph slower than train B. Train A travels ...

Algebra - The speed of train A is 6 mph slower than the speed of train B. Train ...

algebra - The speed of train A is 6 mph slower than the speed of train B. Train ...

math - Train A is 12 mph slower than train B. Train A travels 230 miles in the ...

math - Train A is 12 mph slower than train B. Train A travels 230 miles in the ...

math - the speed of a train a is 6 mph slower than the speed of train b. train a...

algebra 2 - I don't know how to do this the speed of train A is 18mph slower ...