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December 20, 2014

December 20, 2014

Posted by **Francine** on Sunday, September 25, 2011 at 10:40pm.

- College Algebra 2 -
**Reiny**, Sunday, September 25, 2011 at 10:43pmspeed of slower train = x mph

speed of faster train = x+16 mph

time for slow train to go 190 miles = 190/x

time for fast train to go 270 miles = 270/(x+16)

but the times are the same ....

190/x = 270/(x+16)

cross-multiply and solve for x, easy from here.

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