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October 20, 2014

October 20, 2014

Posted by **dian** on Sunday, September 25, 2011 at 10:13pm.

f(x)=square root 9-x

- Pre calculus -
**Steve**, Tuesday, September 27, 2011 at 6:17amYou know that sqrt(u) has domain u>=0. In this case, u = 9-x. So, yu must have

9-x >= 0

9 >= x

or, as usually written

x <= 9

or

{x:x<=9}

or

x in (-oo,9]

depending on desired notation.

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