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October 23, 2014

October 23, 2014

Posted by **sequoia** on Sunday, September 25, 2011 at 6:55pm.

- geometry -
**Steve**, Tuesday, September 27, 2011 at 5:51amI'll do #12. You should be able to follow the method for 13,14.

You calculate the distance between two points by making the line joining them the hypotenuse of a right triangle with horizontal and vertical legs.

In this case, G=(0,0) and H=(-3,4). So, to get the triangle, note that the point P=(-3,0) has as its base the line GP and its height is PH. You could also use the point Q=(0,4), in which case the base would be above the hypotenuse.

In either case, you can now easily see that the legs have length 3 and 4. So, the hypotenuse has length sqrt(3^2 + 4^2) = sqrt(25) = 5.

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