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posted by Anonymous on Sunday, September 25, 2011 at 6:03pm.

a projectile is fired from the surface of the earth with a speed of 200 m/s at an angle of 30 degrees above the horizontal. If the ground is level, what is the maximum height reached by the projectile

h = V^2(sin^2(30))/2g

Vy= sin30(200)=100m/s t=(Vf-Vi)/a, t=(0-100)/9.81, t=10.3s Sy=Vy(t), Sy= 100(10.3), Sy= 1019m

1019M

509.7M

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