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September 2, 2014

September 2, 2014

Posted by **Ruth Joy** on Sunday, September 25, 2011 at 5:35pm.

- Algebra & Trigonometry -
**Steve**, Tuesday, September 27, 2011 at 5:35amIf the original cube had side s, then the volume was s^3.

A 1-inch slab has volume s^2.

So, we know that s^3 - s^2 = 180

s^3 - s^2 - 180 = 0

Inspection reveals that s=6 is one answer. So, now we have

(s-6)(s^2 + 5s + 30)

The quadratic has no real roots, so s=6 is the only answer.

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