Posted by Ruth Joy on Sunday, September 25, 2011 at 5:35pm.
If the original cube had side s, then the volume was s^3.
A 1-inch slab has volume s^2.
So, we know that s^3 - s^2 = 180
s^3 - s^2 - 180 = 0
Inspection reveals that s=6 is one answer. So, now we have
(s-6)(s^2 + 5s + 30)
The quadratic has no real roots, so s=6 is the only answer.
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