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April 19, 2015

Posted by **amy** on Sunday, September 25, 2011 at 5:00pm.

Degree: 6 so I know there's at least 6

zeros:-5-isqrt7, 13 + 2ni, -5 - 3i

(where n is a real number)

any ideas??????

- pre calculus -
**Steve**, Tuesday, September 27, 2011 at 5:25amThe idea is to remember that you're dealing with a polynomial with real coefficients. That means that any complex roots occur in conjugate pairs.

So, that means that the six roots are -5-isqrt7 -5+isqrt7

13+2ni 13-2ni

-5-3i -5+3i

Now you just multiply all the factors together to get the polynomial.

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