Problem 22.2


2 *10^13 electrons flow through a transistor in 1.0ms .



Part A -

What is the current through the transistor?

Express your answer using two significant figures.

in mA

You need to learn what an ampere is.

would the current be 2*10^13 X -1.6*10^-19 divided by 1?

The answer is 3.2

To find the current through the transistor, we need to use the equation:

current = charge / time

First, let's convert the charge from electrons to coulombs. We know that 1 electron carries a charge of 1.6 x 10^-19 coulombs. So, the total charge is:

charge = number of electrons x charge per electron
= 2 x 10^13 x 1.6 x 10^-19 coulombs

Next, let's convert the time from milliseconds to seconds. We know that 1 millisecond is equal to 10^-3 seconds. So, the time is:

time = 1.0 ms x 10^-3 seconds

Now, we can substitute these values into the current equation:

current = (2 x 10^13 x 1.6 x 10^-19 coulombs) / (1.0 ms x 10^-3 seconds)

Simplifying the equation, we have:

current = (3.2 x 10^-6 coulombs) / (1.0 x 10^-3 seconds)

Now, let's simplify the units:

current = 3.2 x 10^-6 coulombs / seconds

To convert the current from coulombs per second to milliamperes (mA), we need to divide by 10^-3:

current = (3.2 x 10^-6 coulombs / seconds) / (10^-3)

Simplifying further, we have:

current = 3.2 x 10^-6 coulombs / (seconds x 10^-3)

current = 3.2 x 10^-6 coulombs / milliseconds

Therefore, the current through the transistor is 3.2 x 10^-6 mA, rounded to two significant figures.