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December 20, 2014

December 20, 2014

Posted by **amy** on Sunday, September 25, 2011 at 4:21pm.

f(x) = x^6 + 2x^5 + 3x^2 - 2x - 16

- precalculus -
**Reiny**, Sunday, September 25, 2011 at 4:34pmf(-2) = (-2)^6 + 2(-2)^5 + 3(-2)^2 -2(-2) - 16

= 64 -64 + 12 + 4 -16

= 0

so what do you think?

- precalculus -
**amy**, Sunday, September 25, 2011 at 4:48pmIt's actually what I got and it is a factor because it's zero right?

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