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September 18, 2014

September 18, 2014

Posted by **Sara** on Sunday, September 25, 2011 at 4:10pm.

Evaluate the improper integral for a>0.

The integral is:

the integral from 0 to infinity, of e^(-y/a)dy

Can anyone help me solve this? When I try I get 'a', which apparently is incorrect. Thank you!

- Calculus 2 -
**Reiny**, Sunday, September 25, 2011 at 4:42pm∫e^(-y/a) dy

= -a(e^(-y/a) from 0 to ∞

= -a/e^(y/a) from 0 to ∞

as y -->∞

a/e^(y/a) ---> 0

so the integral from above

= 0 - (a/e^0) )

= 0 - a/1

= -a

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