Posted by **Amir khan** on Sunday, September 25, 2011 at 7:34am.

1) The first term of arithmetic progression is -20 and the sum of it's term is 250. find it's last term if the number of it's terms is 10

2) Find the fifth term from the arithmetic progression -12, -9, -6 hence find the sum of it's first fifty terms.

3) The sum of the first terms in Arithmetic progression is equal to -24, and the sum of the last six terms equal to 30. if the number of it's term is 12. find a) it's common different

b) The first term

c) the last term

- maths -
**Anonymous**, Tuesday, January 24, 2012 at 4:09am
Answer

- maths -
**ari**, Thursday, January 30, 2014 at 2:40am
3)a=-12

d=3

t(5)=a+(n-1)d

=-12+(5-1)3

=0

s(50)=3625

hope it would be a help. :)

- maths -
**Iddrisu Toarik**, Thursday, November 13, 2014 at 11:28am
U2= a=8/9 U2=8/9 Un= arn-1 if n=2 U2= arn7-1 8/9=2(r6)

- maths -
**adjei**, Thursday, September 24, 2015 at 8:25am
1) a=-20

Sn=250

. n=10

Sn=n/2(2a+(n-1)d)

250=10/2(2(-20)+(10-1)d)

250=5((-40)+(9)d)

250=-200+45d

250+200=45d

d=10

Un=a+(n-1)d

Un=-20*(10-1)10

Un=-20+900

Un=880

::the last term=880

- maths -
**adjei**, Thursday, September 24, 2015 at 8:40am
2) a=-12

. Un=-6

d=-3

n=5

S5=5/2(2(-12)+(5-1)-3)

2.5(-24)+-12)

. 2.5(-36)

S5=-90

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