Posted by **Anonymous** on Sunday, September 25, 2011 at 4:29am.

A linear charge of nonuniform density lambda(x)=bx C/m, where b = 5.2 nC/m2, is distributed along the x-axis from 4.9 m to 6 m.

Determine the electric potential (relative to zero at infinity) of the point y = 8.6 m on the positive y-axis.

- physics -
**bobpursley**, Sunday, September 25, 2011 at 7:04am
Electric potential is scalar, so you just add the incremetnal parts.

V= k INT dq/distance

ok, distance= sqrt(y^2+x^2)

and dq=lambda*x*dx

V=k int lamda x dx /sqrt(y^2+x^2)

V=k*lambda INT x/( ) dx

= k lambda sqrt ( ) over the limits

check all that.

- physics -
**Anonymous**, Sunday, September 25, 2011 at 5:17pm
So going on that

V=[(8.98755e9)*(5.2e-9)*sqrt(8.6^2 + x^2)] from 4.9 to 6?

- physics -
**BL**, Thursday, July 7, 2016 at 9:42pm
:)))))))))))))))))))))))))))GAU

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