physics
posted by Anonymous on .
A linear charge of nonuniform density lambda(x)=bx C/m, where b = 5.2 nC/m2, is distributed along the xaxis from 4.9 m to 6 m.
Determine the electric potential (relative to zero at infinity) of the point y = 8.6 m on the positive yaxis.

Electric potential is scalar, so you just add the incremetnal parts.
V= k INT dq/distance
ok, distance= sqrt(y^2+x^2)
and dq=lambda*x*dx
V=k int lamda x dx /sqrt(y^2+x^2)
V=k*lambda INT x/( ) dx
= k lambda sqrt ( ) over the limits
check all that. 
So going on that
V=[(8.98755e9)*(5.2e9)*sqrt(8.6^2 + x^2)] from 4.9 to 6? 
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