Posted by **Lisa** on Saturday, September 24, 2011 at 5:45pm.

(x-8)(x-k) = x^2-5kx+m

In the equation above, k and m are constants. If the equation is true for all values of x, what is the value of m?

- SAT algebra -
**Reiny**, Saturday, September 24, 2011 at 6:12pm
(x-8)(x-k) = x^2-5kx+m

x^2 - kx - 8x + 8k = x^2 - 5kx + m

x^2 - x(k + 8) + 8k = x^2 - 5kx + m

for the equation to be true

-x(k+8) = -5kx and 8k = m

k+8 = -5k and m = 8k

6k =-8

k = -4/3

then m = 8(-4/3) = -32/3

- SAT algebra -
**Anonymous**, Tuesday, April 24, 2012 at 10:09pm
-x(k+8)=-5kx then why not k+8=5k => k=2 and m=16. why it is k+8=-5k. thought answere was 16. I did not have ansewer choice of -32/3 in the book.

- SAT algebra -
**anon**, Sunday, August 19, 2012 at 4:52pm
yeah, don't pay attention to original answerer... they are totally wrong.

i'm looking for help too :|

- SAT algebra -
**janae**, Wednesday, September 26, 2012 at 5:49pm
Reiny was right until 4th line up from the bottom. when you divide -x out, the equation should read k+8=+5k, not negative. thus, k would become 2, not -4/3 which leads us to m= 16

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