Posted by Lisa on Saturday, September 24, 2011 at 5:45pm.
(x8)(xk) = x^25kx+m
In the equation above, k and m are constants. If the equation is true for all values of x, what is the value of m?

SAT algebra  Reiny, Saturday, September 24, 2011 at 6:12pm
(x8)(xk) = x^25kx+m
x^2  kx  8x + 8k = x^2  5kx + m
x^2  x(k + 8) + 8k = x^2  5kx + m
for the equation to be true
x(k+8) = 5kx and 8k = m
k+8 = 5k and m = 8k
6k =8
k = 4/3
then m = 8(4/3) = 32/3

SAT algebra  Anonymous, Tuesday, April 24, 2012 at 10:09pm
x(k+8)=5kx then why not k+8=5k => k=2 and m=16. why it is k+8=5k. thought answere was 16. I did not have ansewer choice of 32/3 in the book.

SAT algebra  anon, Sunday, August 19, 2012 at 4:52pm
yeah, don't pay attention to original answerer... they are totally wrong.
i'm looking for help too :

SAT algebra  janae, Wednesday, September 26, 2012 at 5:49pm
Reiny was right until 4th line up from the bottom. when you divide x out, the equation should read k+8=+5k, not negative. thus, k would become 2, not 4/3 which leads us to m= 16

SAT algebra  Francis NtiFrimpong, Monday, January 11, 2016 at 8:12pm
x^2 x(k+8)+8k=x^25kx+m
let x(k+8) equivalent to 5kx & let 8k equivalent to m...
(x(k+8))/x=(5kx)x
x crosses out so
k+8=5k....
8=5kk
8=4k
2=k
if 8k=m then 8(2)=m
16=m
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