Thursday

October 2, 2014

October 2, 2014

Posted by **Anonymous** on Saturday, September 24, 2011 at 2:54pm.

h(x)=

-x-3 for x greater than or equal to 1

ax+b for -2<x<1

x(squared) for x less than or equal to -2

Find the values of "a" and "b" that make h(x) continous.

I'm a bit stumped on how to go about solving this one. Help would be greatly appreciated. :)

- calculus -
**Reiny**, Saturday, September 24, 2011 at 3:16pmlook at the transition points, they should be the same.

when x = 1

h(x) = -x - 3 = -1-3 = -4

h(1) = a + b

so a+b = -4

h(-2) for ax+b = -2a+b

h(-2) for x^2 = 4

so -2a + b = 4

a+b = -4

-2a +b = 4

subtract:

3a = -8

a = -8/3,

back in a+b= -4

-8/3+b = 4

b = 20/3

a = -8/3 , b = 20/3

**Answer this Question**

**Related Questions**

math - State the null hypothesis, Ho, and the alternative hypothesis, Ha, that ...

math/calculus - The function f is defined as follows: f(x)={x+6 if -5 less than ...

math - sketch the feasible region for this system of the inqualities and find ...

algebra 2 - how do i find the are of the region defined by |x|+|y| less than or ...

algebra 2 - how do i find the are of the region defined by |x|+|y| less than or ...

Algebra 2 - Okay so I need help with basically how to find the domain, range, ...

Algebra--Correction? - Solve x^2 -3x is greater than or equal to 10 Would the ...

Calculus - Find the constants a and b such that the function is continuous on ...

math - The function f(x)is defined as f(x)={-2x+3: if -2 less than or equal to &...

random variables - For the standard normal random variable Z, compute the ...