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February 1, 2015

February 1, 2015

Posted by **Sybil Jones** on Saturday, September 24, 2011 at 2:45pm.

lim ->0 sin(sin(x))/x^k

exists, and then find the value the limit.

(hint:consider first k=0, then k=1. Find the limit in these simple cases. Next take k=2 and finally consder k>2 and find the limit in these cases as well)

I did this for the first one

lim x->0 sin(sinx))/x^0=0

then idk how to do the other ones

- Calculus -
**bobpursley**, Saturday, September 24, 2011 at 2:46pmk=1 limit sinx/x=1

k=2 limit sinx/x *1/x= undefined

and so on.

- Calculus -
**Sybil**, Saturday, September 24, 2011 at 4:21pmfor k=2 lim x->0 sin(sin(x))/x^2= error

so undefined So do I have to do sided limits? how?

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