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February 1, 2015

February 1, 2015

Posted by **vicki** on Saturday, September 24, 2011 at 12:15pm.

- calculus -
**Reiny**, Saturday, September 24, 2011 at 3:27pmdy/dx = 6x + 5

so at (-1,3), dy/dx = -6+5 = -1

slope = -1, point on line is (-1,3)

3 = (-1)(-1) + b in y = mx+b

2 = b

equation of tangent:

y = -x + 2

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