Posted by **vicki ** on Saturday, September 24, 2011 at 12:15pm.

find an equation of the tangent line to the curve at y=2x^3+5x, (-1, 3)

- calculus -
**Reiny**, Saturday, September 24, 2011 at 3:27pm
dy/dx = 6x + 5

so at (-1,3), dy/dx = -6+5 = -1

slope = -1, point on line is (-1,3)

3 = (-1)(-1) + b in y = mx+b

2 = b

equation of tangent:

y = -x + 2

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