(1)I am thinking of a 5-digit odd number.
(2)The sum of all its digits is 20.
(3) The digits in the hundreds place and in the tens place are consecutive numbers.
When you multiply the digits in the tens and hundreds places, you get the digits for the thousands and ten-thounsands places.What is Rusty's number?
The number is abcde
a+b+c+d+e = 20
d = c+1
c*d = ba
One such number is 24671
Rusty's number is probably 60239
But it said 5-digit odd numbers
Since the ones column digits are both odd, 24,671 and 60,239 are both odd numbers.
A Freight train passed through a town. Behind the engine was the coal car. The cattle car was between the milk car and the lumber car. The open boxcar was in front of the flat car but directly behind the milk car. Of course, a caboose was at the end. In what order were the cars?
The answer is:
The engine, coal car, lumber car, cattle car, milk car, open boxcar, flat car, and the caboose. It's actually really simple..
To solve this problem, let's break it down step by step:
Step 1: We know that the number is odd, which means the digit in the ones place must be odd. Since the sum of all the digits is 20, we can start by finding all possible combinations of four digits that add up to 20.
Step 2: The hundreds and tens place digits are consecutive numbers. This means we need to find pairs of two consecutive numbers that add up to 20 when added to two other digits.
Step 3: To find all the possible combinations, we can start by trying different pairs of consecutive numbers as the hundreds and tens place digits. We will use a trial and error approach.
Let's list all the possibilities:
Pair 1: 1 and 2:
In this case, we have 1 and 2 as the hundreds and tens place digits. So, the remaining two digits must add up to 20 - (1 + 2) = 17.
Possible combinations for the remaining two digits: 8 + 9, 9 + 8, 7 + 10, 10 + 7.
By multiplying the digits in the tens and hundreds places, we get 1 * 2 = 2, which is not a valid solution.
Pair 2: 2 and 3:
In this case, we have 2 and 3 as the hundreds and tens place digits. So, the remaining two digits must add up to 20 - (2 + 3) = 15.
Possible combinations for the remaining two digits: 6 + 9, 9 + 6, 7 + 8, 8 + 7.
By multiplying the digits in the tens and hundreds places, we get 2 * 3 = 6, which gives us a valid solution.
So, Rusty's number is 639.