a car traveling initially at +7.0 m/s accelerates uniformly at the rate of +0.80m/s2 for a distance of 245 m. what is its velocity at the end of the acceleration?
physics - Steve, Friday, September 23, 2011 at 4:58pm
Just get out your good old
v = at
s = 1/2 at^2
formulas and work with them a bit.
We want to find out how long it will take to go 245m under acceleration.
245 = 7t + .4t^2
t = 17.5 sec
v = 7 + .8*17.5 = 21.0 m/s