Saturday

August 23, 2014

August 23, 2014

Posted by **Laurie** on Thursday, September 22, 2011 at 9:34pm.

- calculus -
**Steve**, Friday, September 23, 2011 at 3:29pmNow, the slope of the tangent line at any point (x,y) on the curve is just y'(x) = cosx

At x=pi, y' = -1 and y=3

So, we want the line through (pi,3) with slope -1.

y-3 = -(x-pi) = pi-x

y = -x + 3+pi

The slope of the normal line is -(1/-1) = 1

y-3 = (x-pi)

y = x + 3-pi

**Related Questions**

Calculus - (A) Find the equations of the tangent lines to the circle x^2 +y^2=25...

cal - Equations of the tangent lines to hyperbola xy=1 that pass through point...

Ap Calc AB - Find the equation of the line normal to the curve at (0,0). (Normal...

calculus - Given that x3-axy+3ay2=3a3 Find the equations for the tangent and ...

Calculus - Find equations of the tangent lines at all inflection points of the ...

Calculus (Urgent Help) - The graph of y=cos x * ln cos^2x has seven horizontal ...

Calculus (Urgent Help) - The graph of y=cos x * ln cos^2x has seven horizontal ...

Calculus (Help) - The graph of y=cos x * ln cos^2x has seven horizontal tangent ...

Calculus (Help) - The graph of y=cos x * ln cos^2x has seven horizontal tangent ...

calculus - f(x)=kx^2+3 a) if the tangent lines to the graph of f at (t,f(t)) and...