Posted by **JP** on Thursday, September 22, 2011 at 9:03pm.

Stan takes a trip, driving with a constant velocity of 81.5 km/h to the north except for a 22 min rest stop. If Stan's avg velocity is 66.80 km/h to the north, how long does the trip take?

- Physics -
**Steve**, Friday, September 23, 2011 at 2:01pm
Let the driving time be t hours.

The distance covered is 81.5t km.

However, if we factor in the rest stop of 22/60 hours, the distance is 66.8(t+22/60).

Equating the two distances, we get

66.8(t+22/60) = 81.5t

66.8t + 25 = 81.5t

25 = 14.7t

t = 1.7 hours driving, so

the trip took 1hr 42min + 22min = 2hr 4min

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