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August 1, 2014

August 1, 2014

Posted by **M** on Thursday, September 22, 2011 at 8:14pm.

f(x) = -3^3 - 6x^2 + 10x + 9 ; [-1,0]

- Calculus -
**Steve**, Friday, September 23, 2011 at 1:21pmf(-1) = -4

f(0) = 9

So, the IVT says that f(x) = 0 for x somewhere in [-1,0]

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