Posted by **Whitney** on Thursday, September 22, 2011 at 3:30pm.

The projectile motion is fired with velocity of magnitude vo at the angle feta. Find feta for which the maximum elevation of the projectile is twice its range

- Physics -
**bobpursley**, Thursday, September 22, 2011 at 3:38pm
feta is a cheese, not much else. Theta is a Greek letter that is often used for an angle. But feta? it won't hold up more than about 30 degrees, and even then if falls down.

Vertical height=2*horiztal distance.

So vertical height first:

at the top, vertical velocity is zero.

vtop=vo*sinTheta-g t

or time to top is vo*sinTheta/g

then verticalmax height is

hmax=vo*sinTheta*vo*sinTheta/g

horizontal distance:

vo*cosTheta* vo sinTheta/g

then

vertical max=2*horizontal

(vo*sinTheta)^2 /g = 2*(vo^2 cosTheta*sinTheta)/g

or sintheta=2costheta

tan Theta=2

theta=arcTan2 or = 63.4349488 degrees

check all this.

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