Posted by Anonymous on Thursday, September 22, 2011 at 3:18pm.
Differentiate with respect to x (3x^2-5ax+a^2)^4
- calculus - Steve, Thursday, September 22, 2011 at 4:09pm
This is a typical problem using the chain rule: if y = f(u) and u = g(x), then dy/dx = dy/du * du/dx
Here, let u = 3x^2 - 5ax + a^2
So, y = u^4
dy/du = 4u^3
du/dx = 6x - 5a
dy/dx = 4u^3 * (6x-5a)
= 4(3x^2 - 5ax + a^2)^3 * (6x-5a)
Don't let the a's bother you. They're just some number, like 3 or -4, just one we don't happen to know. Just carry them through like any other constant.
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