If a car moves at 36km/h accelerate uniformly at 4m/s calculate it velocity in 2 seconds.
Vo = 36000m/h * (1/3600)h/s = 10m/s.
Vf = Vo + at,
Vf = 10 + 4*2 = 18m/s
A body is moving with an initial velocity of 36km/hr accelerates uniformly at the rate of 4m/s for 15s. Calculate the total distance travelled ...
To calculate the velocity of the car after 2 seconds, we need to first find its initial velocity and then use the acceleration to determine how much it has changed over the given time.
Given:
Initial velocity (u) = 36 km/h (Note: We need to convert this to m/s)
Acceleration (a) = 4 m/s^2
Time (t) = 2 seconds
Converting initial velocity from km/h to m/s:
1 km/h = 1000 m/3600 s = 10/36 m/s
Therefore, the initial velocity (u) = 36 km/h x 10/36 m/s = 10 m/s
Using the first equation of motion:
v = u + at
Substituting the given values:
v = 10 m/s + 4 m/s^2 * 2s
Calculating the final velocity (v):
v = 10 m/s + 8 m/s = 18 m/s
Therefore, the velocity of the car after 2 seconds of acceleration is 18 m/s.