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October 23, 2014

October 23, 2014

Posted by **Sabrina** on Thursday, September 22, 2011 at 12:48pm.

(a) the time taken to reach 15 ms-1

(b) the distance travelled during this time

(c) the velocity of the car when it was 100 m from the start point

- Physics -
**Henry**, Saturday, September 24, 2011 at 3:57pma. t = (Vf - Vo) / a,

t = (15 - 50) / -10 = 3.5s.

b. d = Vo*t + 0.5a*t^2,

d = 50*3.5 + (-5)(3.5)^2 = 113.75m.

c. Vf^2 = Vo^2 + 2a*d,

Vf^2 = (50)^2 + (-20)100 = 500,

Vf = 22.36m/s.

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