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Posted by on Thursday, September 22, 2011 at 10:20am.

Find the dy/dt for each pair of functions y=x^2-5x , x=t^2+3

  • math - , Thursday, September 22, 2011 at 11:49am

    from y = x^2 - 5x
    dy/dx = 2x - 5

    from x = t^2+3
    dx/dt = 2t

    dy/dt = (dy/dx)(dx/dt)
    = (2x-5)(2t)

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