Posted by **Alex** on Thursday, September 22, 2011 at 4:20am.

an object is launched from ground level with an initial velocity of 400 feet per second. To the nearest tenth off a second, how long does it take the object to reach a height off 650 feet?

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**Henry**, Friday, September 23, 2011 at 6:49pm
h = Vo*t + 0.5g*t^2 = 650 Ft,

400t + 16t^2 = 650,

16t^2 + 400t -650 = 0,

Use Quadratic Formula to find t:

t = 1.53s.

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