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December 20, 2014

December 20, 2014

Posted by **John** on Thursday, September 22, 2011 at 4:12am.

- Physics -
**ZHENGGUO (KEVIN)**, Sunday, June 8, 2014 at 10:45pmFFirst, we analyse the Vertical axis, to keep the s-man from falling, the upward friction force must equal to the downward W, which is m*g. Thus, we derive the equation f=μ*Normal force=m*g=W

SSecond, let's focus on the horizontal axis, the force components on the horizontal axis are Normal force and applied force by the truck. but in this case, the Normal force IS the applied force. so the Fnet=Normal force=m*a.

now let's plug the "Normal force = m*a" from the SSecond part into the equation "μ*Normal force=m*g" from the FFirst part. so we get the equation "μ* m* a=m* g". both m cancel out, and we get "μ*a=9.8".

value of μ is given, which is 0.65. so finally "a= 9.8/0.65=15.0769...m/s^2"

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