Saturday

October 25, 2014

October 25, 2014

Posted by **snow** on Thursday, September 22, 2011 at 1:14am.

- pre-calculus -
**Steve**, Thursday, September 22, 2011 at 11:44amLet's set up some variables to keep track of the various items of interest.

a = # par-3 holes

b = # par-4 holes

c = # par-5 holes

We are told:

a+b+c=18 holes

b = 7c

a+c = 4

3a+4b+5c = 72 strokes needed to finish course

3(4-c) + 4(7c) + 5c = 72

12-3c + 28c + 5c = 72

30c = 60

c=2

b=14

a=2

And we didn't even need the fact that a+b+c=18, but it works out just fine.

**Answer this Question**

**Related Questions**

Algebra - On an 18-hole golf course, there are par-3 holes, par-4 holes, and par...

Calculus - On an 18-hole golf course, there are par-3 holes, par-4 holes and par...

Math - In golf, the average score a food player should be able to achieve is ...

probability - Chris has a chance of making par on each hole that he plays. Today...

math - 6. Joe played golf with Sam on a speacial par 3 course.. They played nine...

Math - In a golf math Jesse scored 5 over par Neil scored 3 under par, Felipo ...

physics - Two circular holes, one larger than the other, are cut in the side of ...

MAths algebra - Tiger woods won the Buick Invitational.The following scorecard ...

Intermediate Algebra - Andrews factored expressions -6x63+9x^2-3x as -3x(2x^2-3x...

math30 - The Mean and the Standard Deviation Last year, golfers at Smith Ranch ...