Find the zeroes of the function algebraically.
f(x)= �ã-7x-2
shoot, sorry that box and then a was a square root symbol on my word processory but it appears on this as a box and special a? strange..
sqrt ( - 7 x - 2 ) = 0 Square both sides
- 7 x - 2 = 0 Add 2 to both sides
- 7 x - 2 + 2 = 0 + 2
- 7x = 2 Divide both sides with -7
x = - 2 / 7
Sweet, thanks!!! :)
To find the zeroes of the function algebraically, we need to solve the equation f(x) = 0. In this case, the function is f(x) = -7x - 2.
Setting f(x) equal to zero, we have:
-7x - 2 = 0
To solve for x, we can isolate x by performing some algebraic manipulations. First, we can add 2 to both sides of the equation:
-7x = 2
Next, divide both sides of the equation by -7 to solve for x:
x = 2 / -7
Therefore, the zero of the function f(x) = -7x - 2 is x = 2 / -7, which is approximately equal to -0.2857.