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August 28, 2014

August 28, 2014

Posted by **ryan** on Wednesday, September 21, 2011 at 9:32pm.

- math -
**Steve**, Thursday, September 22, 2011 at 5:11pmIf we use h and w for length and width, with length parallel to the road,

perimeter p = 2w+h = 248

Area = w*h = w(248-2w) = 248w - 2w^2

We want to maximize the area, so we take the derivative and set it to zero.

248-4w = 0

w = 62

So, h = 124

Maximum area = 62*124 = 7688 sq ft

For a given perimeter, a square has maximum area. Here, we use the road as one side, so we get to enclose two squares instead of one.

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