Posted by **Anonymous** on Wednesday, September 21, 2011 at 8:12pm.

A tree grows 2.80 m during the first year since it was planted. During each subsequent year the tree's growth is 85% of its growth the previous year.

a) Calculate to the nearest 0.001m, the growth of the tree in the fourth year.

Tn = ar^n-1

T4 = 2.80(0.85)^10-1

T4 = 2450

I don't get how to do this, the answer is wrong, its supposed to be 1.72m :\

Determine the first year in which the growth of the tree is less than half a metre.

- Calculus -
**Reiny**, Wednesday, September 21, 2011 at 8:27pm
Where in the world did you get 10 in the 10-1

should have been 4-1

T4 = 2.8(.85)^3 = 1.719 or 1.72

for growth to be .5

.5 = 2.8(.85)^(n-1)

divide by 2.8

.17857.. = .85^(n-1)

take log of both sides

log (.17857..) = log [.85^(n-1)]

log (.17857..) = (n-1)log [.85]

n-1 = log (.17857..) / log [.85] = 10.6

n = 11.6

in year 11, growth = 2.8(.85)^10 = .5512

in year 12, growth = 2.8(.85)^11 = .468

so what do you think?

- Calculus -
**Anonymous**, Wednesday, September 21, 2011 at 8:35pm
So that would be Year 12.

- Calculus -
**Reiny**, Wednesday, September 21, 2011 at 8:36pm
yes

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