Posted by Anonymous on Wednesday, September 21, 2011 at 8:12pm.
A tree grows 2.80 m during the first year since it was planted. During each subsequent year the tree's growth is 85% of its growth the previous year.
a) Calculate to the nearest 0.001m, the growth of the tree in the fourth year.
Tn = ar^n-1
T4 = 2.80(0.85)^10-1
T4 = 2450
I dont get how to do this, the answer is wrong, its supposed to be 1.72m :\
Determine the first year in which the growth of the tree is less than half a metre.
- Calculus - Reiny, Wednesday, September 21, 2011 at 8:27pm
Where in the world did you get 10 in the 10-1
should have been 4-1
T4 = 2.8(.85)^3 = 1.719 or 1.72
for growth to be .5
.5 = 2.8(.85)^(n-1)
divide by 2.8
.17857.. = .85^(n-1)
take log of both sides
log (.17857..) = log [.85^(n-1)]
log (.17857..) = (n-1)log [.85]
n-1 = log (.17857..) / log [.85] = 10.6
n = 11.6
in year 11, growth = 2.8(.85)^10 = .5512
in year 12, growth = 2.8(.85)^11 = .468
so what do you think?
- Calculus - Anonymous, Wednesday, September 21, 2011 at 8:35pm
So that would be Year 12.
- Calculus - Reiny, Wednesday, September 21, 2011 at 8:36pm
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