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posted by jasmine on Wednesday, September 21, 2011 at 8:02pm.
how do you find all the real zeros for this function f(x)=x^3+9x^2-4x-36
your expression factors by grouping let x^3 + 9x^2 - 4x - 36 = 0 x^2(x+9) - 4(x+9) = 0 (x+9)(x^2-4) = 0 (x+9)(x+2)(x-2) = 0 x = -9, -2, 2
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