jason drives due west with a speed of 35.0 mi/h for 30.0 min, then continues in the same direction at 60 mi/h for 2.00 hrs, then farther west at 25 mi/h for 10.00 minutes, What is Jason's average velocity
Well, Jason seems to have a need for speed! Let's calculate his average velocity, shall we?
To find average velocity, we need to first find the total displacement and total time. So, let's break it down.
Jason drives at 35.0 mi/h for 30.0 min, which is a total displacement of (35.0 mi/h) * (0.5 h) = 17.5 miles.
Then, he continues at 60 mi/h for 2.00 hrs, which is a total displacement of (60 mi/h) * (2.0 h) = 120 miles.
Finally, he goes at 25 mi/h for 10.00 minutes, which is a total displacement of (25 mi/h) * (0.17 h) = 4.25 miles.
So, the total displacement is 17.5 miles + 120 miles + 4.25 miles = 141.75 miles.
The total time is 30.0 minutes + 2.00 hours + 10.00 minutes = 2.5 hours.
Average velocity is displacement divided by time, so average velocity = 141.75 miles / 2.5 hours ≈ 56.7 miles/hour.
So, Jason's average velocity is approximately 56.7 miles/hour.
Keep on driving in the fast lane, Jason! (But watch out for clowns on the road!)
To find Jason's average velocity, we need to calculate the total displacement and divide it by the total time.
First, let's convert the given times into hours:
30.0 min = 30.0/60 = 0.5 hrs (since there are 60 min in an hour)
2.00 hrs = 2.00 hrs (already in hours)
10.00 min = 10.00/60 = 0.1667 hrs
Now, let's determine the displacements for each leg of the journey:
In the first leg, Jason drives due west with a speed of 35.0 mi/h for 0.5 hours. Therefore, the displacement for this leg is:
Displacement1 = Speed1 x Time1 = 35.0 mi/h x 0.5 hrs = 17.5 miles west
In the second leg, Jason continues in the same direction at 60.0 mi/h for 2.00 hours. Therefore, the displacement for this leg is:
Displacement2 = Speed2 x Time2 = 60.0 mi/h x 2.00 hrs = 120.0 miles west
In the third leg, Jason drives farther west at 25.0 mi/h for 0.1667 hours. Therefore, the displacement for this leg is:
Displacement3 = Speed3 x Time3 = 25.0 mi/h x 0.1667 hrs ≈ 4.167 miles west
To find the total displacement, we sum up the individual displacements:
Total Displacement = Displacement1 + Displacement2 + Displacement3
= 17.5 miles + 120.0 miles + 4.167 miles
= 141.667 miles west
To find the total time, we sum up the individual times:
Total Time = Time1 + Time2 + Time3
= 0.5 hrs + 2.00 hrs + 0.1667 hrs
= 2.6667 hours
Finally, we can calculate Jason's average velocity:
Average Velocity = Total Displacement / Total Time
= 141.667 miles / 2.6667 hours
≈ 53.12 mi/h
Therefore, Jason's average velocity is approximately 53.12 mi/h, west.