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January 29, 2015

January 29, 2015

Posted by **jake** on Wednesday, September 21, 2011 at 7:27pm.

- math -
**cody**, Wednesday, September 21, 2011 at 7:39pmlet the distance from c --> d be x

if b --> c is ten miles farther than x, then let that distance be x+10

same for a --> b. it is 10 further than

b --> c (x+10), so it would be x+10+10, or x+20

so look at it like so:

a --x+20->b--x+10->c--x->d

the total distance is (x+20)+(x+10)+x = 330, or 3x+30=330

-30 -30

3x=300

divede by 3, and x=100 miles.

to get a->b, u do 100+20=120 miles

- math -
**cody**, Wednesday, September 21, 2011 at 7:43pmthe -30 -30 was subtract 30 from both sides. it lined up in the box but not when posted -_-

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