Posted by **cody** on Wednesday, September 21, 2011 at 6:52pm.

well i'm stumped. i can't figure out how to solve this.

solve for (x,y):

3/x + 2/y = 0

5/x - 1/y = 13

i can't graph it, and i can't use a calculator. i keep getting stuck on the second equation b/c i get 5y -13xy -x=0 and since 13 is a prime number i cant figure out what to do next.

- algebra -
**Reiny**, Wednesday, September 21, 2011 at 7:29pm
first:

3/x + 2/y = 0

times xy

3y + 2x = 0

y = -2x/3

in 2nd:

times xy

5y - x = 13xy

sub in y = -2x/3

5(-2x/3) - x = 13x(-2x/3)

-10x/3 - x = -26x^2/3

times 3

-10x - 3x = -26x^

26x^2 - 13x = 0

13x(2x - 1) = 0

x = 0 or x = 1/2

but x cannot be zero or else we divided by zero in each equation, that would be undefined

x = 1/2

then y = (-2/3)(1/2) = -1/3

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