Posted by Taylor on Wednesday, September 21, 2011 at 4:26pm.
a rock is dropped from a height of 15m above the ground. when it hits the ground, it leaves a hole 12cm deep. what is the speed of the rock when it hits the ground? what is the deceleration of the rock when it hits the ground?

physics  Henry, Friday, September 23, 2011 at 11:25am
1. Vf^2 = Vo^2 + 2g*d,
Vf^2 = 0 + 19.6*15 = 294,
Vf = 17.15m/s.
2. a = (Vf^2  Vo^2) / 2d,
a = (0  (17.15)^2) / 24 = 12.26s.

physics  Henry, Friday, September 23, 2011 at 11:32am
Correction: a = 12.26m/s^2.
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