Sunday
March 26, 2017

Post a New Question

Posted by on .

An arrow is shot verticaaly upward. Two seconds later, it is at a height of 42 meters ( although this is not necessarily the highest point). with what speed was the arrow shot? how long is the arrow in flight altogether?

  • physics - ,

    1. h = Vo*t + 0.5g*t^2 = 42m,
    Vo*2 + (-4.9)*2^2 = 42,
    2Vo - 19.6 = 42,
    2Vo = 42 + 19.6 = 61.6,
    Vo = 30.8m/s.

    2. t(up) = (Vf - Vo / g,
    t(up) = (0 - 30.8) / -9.8 = 3.14s.

    t(dn) = t(up) = 3.14s.

    T=t(up) + t(dn) = 3.14 + 3.14 = 6.28s.=
    Time in flight.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question